Genetics question?

In horses, black color (B) is dominant to chestnut (b) and trotting gait (T) is dominant to pacing (t). A cross is made between a horse that is homologous both for pacing gait and for black color, and a horse that is homozygous both for trotting gait and chestnut color. What is the expected genotypic ratio of their offspring?

A) 100% Bbtt, B) 50% BBtt and 50% bbTT, C) 100% bbTT, D) 100% BbTt, and/or E) 100%BT

please state one of the above and if possible why.

Thank-you

Genetics question?
BBtt x bbTT



Only two possible gametes: Bt %26amp; bT

So, 100% will have the genotype BbTt



D. is the answer. All of the F1 generation will have the phenotype (heterozygous) Black trotting horse.
Reply:ans is 100%BbTt

horse1- BBtt

horse 2-bbTT

now horse 1 have all th gametes as Bt whereas horse 2 has all th gametes as bT

therefore only cross possible between them is BbTt.
Reply:D for sure
Reply:The first horse listed will be BBtt (homologous means the same). The possible gametes (groups of 2 alleles) for this horse are all Bt. The second horse will be bbTT. Its possible gametes are all bT. Combining Bt and bT will give you 100% BbTt. The answer is D.